tag:blogger.com,1999:blog-8883034.post6605720186433631750..comments2024-03-23T23:26:40.813+01:00Comments on atdotde: How to obtain a polymer Hilbert spaceRoberthttp://www.blogger.com/profile/06634377111195468947noreply@blogger.comBlogger8125tag:blogger.com,1999:blog-8883034.post-83082289057156172382019-07-17T10:12:49.066+02:002019-07-17T10:12:49.066+02:00This comment has been removed by a blog administrator.Nina Athenahttps://www.blogger.com/profile/11942457078940283392noreply@blogger.comtag:blogger.com,1999:blog-8883034.post-51330866467605759362010-04-19T06:11:18.262+02:002010-04-19T06:11:18.262+02:00Nice post Robert. Last time I came to say hello I ...Nice post Robert. Last time I came to say hello I was confused in spelling polymer versus pohlmeyer lol!Mahndisa S. Rigmaidenhttps://www.blogger.com/profile/08507292526980604567noreply@blogger.comtag:blogger.com,1999:blog-8883034.post-13668791333278380132010-04-18T14:34:25.600+02:002010-04-18T14:34:25.600+02:00I should be more clear: If I use your formula for ...I should be more clear: If I use your formula for k=0 I get<br />x*1 = [(1+iex) - 1]/e <br />with e being your epsilon.<br />and thus x*1 = i*x which implies x=0.wolfganghttp://tsm2.blogspot.comnoreply@blogger.comtag:blogger.com,1999:blog-8883034.post-21340672011747508962010-04-18T14:09:24.582+02:002010-04-18T14:09:24.582+02:00It seems that phi=1 is an eigenstate of p (eigenva...It seems that phi=1 is an eigenstate of p (eigenvalue 0) but also an eigenstate of x. But I am perhaps confused about that...wolfganghttp://tsm2.blogspot.comnoreply@blogger.comtag:blogger.com,1999:blog-8883034.post-39584042745229723022010-04-18T12:06:42.932+02:002010-04-18T12:06:42.932+02:00What do you mean by "a problem for x"? O...What do you mean by "a problem for x"? Of course, the constant is not normalised with respect to the usual L^2 measure, but we specify the appropriate polymer measure below.Roberthttps://www.blogger.com/profile/06634377111195468947noreply@blogger.comtag:blogger.com,1999:blog-8883034.post-62236856419800532012010-04-18T11:35:18.217+02:002010-04-18T11:35:18.217+02:00Robert,
I do not understand this part:
"Thus...Robert,<br /><br />I do not understand this part:<br />"Thus we declare the constant wave function psi(x)=1 to be an element of the Hilbert space and we can assume that it is normalised"<br /><br />Does this not already contain a problem for x?wolfganghttp://tsm2.blogspot.comnoreply@blogger.comtag:blogger.com,1999:blog-8883034.post-50160247850773072632010-03-29T13:19:39.999+02:002010-03-29T13:19:39.999+02:00This comment has been removed by a blog administrator.Dolphinhttps://www.blogger.com/profile/16284076880473508250noreply@blogger.comtag:blogger.com,1999:blog-8883034.post-36357152372209568952010-02-10T21:47:16.391+01:002010-02-10T21:47:16.391+01:00It's interesting to note that these issues wer...It's interesting to note that these issues were discussed in a series of papers in the 50's and 60's by Schwinger. <br />The paper that is most relevant to the discussion at hand is <br />``Unitary transformations and the action principle'', http://www.pnas.org/content/46/6/883.full.pdfStam Nicolishttp://www.lmpt.univ-tours.fr/~nicolisnoreply@blogger.com